Student
Name:Tambe
Sanjay Baban
Program Name:Write a program
to accept the information of five students such as rollno,name, and address.And display the information
using structures.
#include<stdio.h>
#include<conio.h>
void
main()
{
struct student
{
int rollno;
char sname[21];
char address[53];
}stud[5];
int
i;
clrscr();
printf("\n
Enter student information");
for(i=0;i<5;i++)
{
printf("\n Enter roll no-");
scanf("\n %d",&stud[i].rollno);
printf("\n Enter the student
name-");
scanf("\n %s",stud[i].sname);
printf("\n Enter the address-");
scanf("\n %s",&stud[i].address);
}
printf("\n
The student information");
for(i=0;i<5;i++)
{
printf("\n roll no
is-%d",stud[i].rollno);
printf("\n name is -%s",stud[i].sname);
printf("\n address is
-%s",stud[i].address);
}
getch();
}
/*
Output
Enter student information
Enter roll no-153
Enter the student name-sanjay
Enter the address-baramati
Enter roll no-149
Enter the student name-sachin
Enter the address-lonibhapkar
Enter roll no-135
Enter the student name-pramod
Enter the address-supe
Enter roll no-111
Enter the student name-ranjit
Enter the address-satara
Enter roll no-130
Enter the student name-chetan
Enter the address-malegaon
The student information
roll no is -153
name is -sanjay
address is -baramati
roll no is -149
name is -sachin
address is -lonibhapkar
roll no is -135
name is -pramod
address is -supe
roll no is -111
name is -ranjit
address is -satara
roll no is -130
name is -chetan
address is –malegaon */
Student
Name:Tambe
Sanjay Baban Roll No:153
Program Name:
Write
a program to accept the information such as roll no, name, 3subjects.
Calculate total, average and display information in descending order of marks.
#include<stdio.h>
#include<conio.h>
void
main()
{
struct
student
{
int rollno;
char name [30];
int mark [3];
int total;
float avg;
}stud[5];
int
i,j;
struct
student temp;
clrscr();
printf("\n
enter student info");
for(i=0;i<5;i++)
{
printf("\n enter the rollno-");
scanf("\n %d",&stud[i].rollno);
printf("\n enter the name-");
scanf("\n %s",&stud[i].name);
stud[i].total=0;
printf("\n enter the mark-");
for(j=0;j<3;j++)
{
scanf("\n
%d",&stud[i].mark[j]);
stud[i].total=stud[i].total+stud[i].mark[j];
stud[i].avg=stud[i].total/3;
}
}
for(i=0;i<5;i++)
{
for(j=i+1;j<3;j++)
{
if(stud[i].total<stud[j].total)
{
temp=stud[i];
stud[i]=stud[j];
stud[j]=temp;
}
}
}
printf("\n
student info");
for(i=0;i<5;i++)
{
printf("\n rollno
%d",stud[i].rollno);
printf("\n name is
%s",stud[i].name);
printf("\n total is
%d",stud[i].total);
printf("\n avg is %f",stud[i].avg);
}
getch();
}
/*
Output
enter student info
enter the rollno-153
enter the name-Sanjay
enter the mark-57
58
68
enter the rollno-149
enter the name-Sachin
enter the mark-68
59
74
enter the rollno-121
enter the name-Subham
enter the mark-55
75
68
enter the
rollno-148
enter the name-Pramod
enter the mark-52
84
70
enter the rollno-142
enter the name-Omkar
enter the mark-54
63
67
student info
rollno 153
name is Sanjay
total is 223
avg is 74.000000
rollno 149
name is Sachin
total is 222
avg is 74.000000
rollno 121
name is Subham
total is 198
avg is 66.000000
rollno 148
name is Pramod
total is 206
avg is 68.000000
rollno 142
name is Omkar
total is 184
avg is 61.000000 */
Student
Name:Tambe
Sanjay Baban Roll No:153
Program Name: Write
a program to student structure and display record in ascending order of student name.
#include<stdio.h>
#include<conio.h>
#include<string.h>
void
main()
{
struct
student
{
int rollno;
char name[21];
char address[53];
}stud[5];
int
i,j;
struct
student temp;
clrscr();
printf("\nEnter
the student info-");
for(i=0;i<5;i++)
{
printf("\n Enter student roll no-");
scanf("\n %d",&stud[i].rollno);
printf("\n Enter student name-");
scanf("\n %s",&stud[i].name);
printf("\n Enter the address-");
scanf("\n %s",&stud[i].address);
}
for(i=0;i<5;i++)
{
for(j=i+1;j<5;j++)
{
if(strcmp(stud[i].name,stud[j].name)>0)
{
temp=stud[i];
stud[i]=stud[j];
stud[j]=temp;
}
}
}
printf("\n
The Student information -");
printf("\n
ROLLNO \t NAME \t ADDRESS");
for(i=0;i<5;i++)
{
printf("\n %d \t %s \t
%s",stud[i].rollno,stud[i].name,stud[i].address);
}
getch();
}
/*Output
Enter the student info-
Enter student
roll no-153
Enter student
name-Sanjay
Enter the
address-Baramati
Enter student roll no-149
Enter student name-Mahesh
Enter the address-Pune
Enter student roll no-108
Enter student name-Akshay
Enter the address-Malegoan
Enter student roll no-135
Enter student name-Pramod
Enter the address-Supe
Enter student roll no-142
Enter student name-Omkar
Enter the address-Indapur
The Student
information -
ROLLNO
NAME ADDRESS
108 Akshay Malegoan
149 Mahesh Pune
142 Omkar
Indapur
135 Pramod Supe
153 Sanjay Baramati */
Student Name:Tambe Sanjay Baban Roll
No:153
program name:menu driven program for
- Add book information
- Display book information
-List all books of given author
-List the count of books in
the library
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
{
struct book
{
int bno;
char bname[20];
char author[20];
};
struct book b[20];
int i,n,ch;
char name[20],c;
clrscr();
while(1)
{
printf("\n
menues");
printf("\n
1.Add book information");
printf("\n
2.display book information");
printf("\n
3.list all boooks of given author");
printf("\n
4.list the count of books in this library");
printf("\n
5. exit from program");
printf("\n
Enter your choice=");
scanf("%d",&ch);
switch(ch)
{
case 1: printf("\n How
many info.you want to add=");
scanf("\n
%d",&n);
for(i=0;i<n;i++)
{
printf("Enter
the book.no=");
scanf("\n
%d",&b[i].bno);
printf("Enter
the book name=");
scanf("\n
%s",&b[i].bname);
printf("Enter
the author name=");
scanf("\n
%s",&b[i].author);
}
break;
case 2:
printf("\n BNO\t BOOKNAME\tBOOKAUTHOR");
for(i=0;i<n;i++)
printf("\n
%d\t%s\t%s",b[i].bno,b[i].bname,b[i].author);
break;
case 3:
printf("Enter
the author name you want=");
scanf("%s",&name);
printf("\n
book information");
printf("\n
BNO\t BOOKNAME\tBOOKAUTHOR");
for(i=0;i<n;i++)
{
if(strcmp(name,b[i].author)==0)
{
printf("\n%d\t
%s\t %s",b[i].bno,b[i].bname,b[i].author);
}
}
break;
case 4:
printf("The
number of book in liabrary are=%d",n);
break;
case 5: exit(0);
default
:printf("\nEnter you correct choice");
}
}
getch();
}
/*
Output
menues
1.Add book information
2.display book information
3.list all boooks of given author
4.list the count of books in this
library
5. exit from program
Enter your choice=1
How many info.you want to add=2
Enter the book.no=101
Enter the book name=cprogramming
Enter the author name=verma
Enter the book.no=102
Enter the book name=statistics
Enter the author name=patil
menues
1.Add book information
2.display book information
3.list all boooks of given author
4.list the count of books in this library
5. exit from program
Enter your choice=2
BNO BOOKNAME BOOKAUTHOR
101
cprogramming verma
102
statistics patil
menues
1.Add book information
2.display book information
3.list all boooks of given author
4.list the count of books in this library
5. exit from program
Enter your choice=3
Enter the author name you
want=patil
book information
BNO
BOOKNAME BOOKAUTHOR
102 statistics patil
menues
1.Add book information
2.display book information
3.list all boooks of given author
4.list the count of books in this library
5. exit from program
Enter your choice=4
The number of book in liabrary
are=2
menues
1.Add book information
2.display book information
3.list all boooks of given author
4.list the count of books in this library
5. exit from program
Enter your choice=5 */
Student
Name:Tambe
Sanjay Baban
Program
Name: Write a program to create customer
structure fields are accno, custname,balance.Display the customer details
whose balance below rs.100 using function.
#include<stdio.h>
#include<conio.h>
struct
customer
{
int accno;
char name[20];
int balance;
}cust[5];
void
display(struct customer[5]);
void
main()
{
struct
customer c[5];
clrscr();
display(c);
getch();
}
void
display(struct customer cust[5])
{
int
i;
printf("\n enter customer information");
for(i=0;i<5;i++)
{
printf("\n enter the account
no:");
scanf("%d",&cust[i].accno);
printf("\n enter the custmer
name:");
scanf("%s",&cust[i].name);
printf("\n enter the
balance:");
scanf("%d",&cust[i].balance);
}
for(i=0;i<5;i++)
{
if(cust[i].balance<100)
{
printf("\n\t%d",cust[i].accno);
printf("\t%s",cust[i].name);
}
}
}
/* Output
enter the
account no:10021
enter the
custmer name:Sanjay
enter the
balance:51000
enter the
account no:50002
enter the
custmer name:Swapnil
enter the
balance:60000
enter the
account no:60506
enter the
custmer name:makarand
enter the
balance:75000
enter the
account no:40005
enter the
custmer name:Pramod
enter the
balance:81000
enter the
account no:30008
enter the
custmer name:Ajit
enter the
balance:51000
10021 Sanjay
50002 Swapnil
60506 makarand
40005 Pramod
30008 Ajit */
